5+(4-t)=8-(2+t)

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Solution for 5+(4-t)=8-(2+t) equation: 



5+(4-t)=8-(2+t)

We move all terms to the left:

5+(4-t)-(8-(2+t))=0

We add all the numbers together, and all the variables

(-1t+4)-(8-(t+2))+5=0

We get rid of parentheses

-1t-(8-(t+2))+4+5=0



We calculate terms in parentheses: -(8-(t+2)), so:

8-(t+2)

determiningTheFunctionDomain
-(t+2)+8

We get rid of parentheses

-t-2+8

We add all the numbers together, and all the variables

-1t+6

Back to the equation:

-(-1t+6)



We add all the numbers together, and all the variables

-1t-(-1t+6)+9=0

We get rid of parentheses

-1t+1t-6+9=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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