5+(2/3x)=-x+20

Solution for 5+(2/3x)=-x+20 equation:

5+(2/3x)=-x+20

We move all terms to the left:

5+(2/3x)-(-x+20)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3x)-(-1x+20)+5=0

We get rid of parentheses

2/3x+1x-20+5=0

We multiply all the terms by the denominator


1x*3x-20*3x+5*3x+2=0

Wy multiply elements

3x^2-60x+15x+2=0

We add all the numbers together, and all the variables

3x^2-45x+2=0

a = 3; b = -45; c = +2;
Δ = b2-4ac
Δ = -452-4·3·2
Δ = 2001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2001}}{2*3}=\frac{45-\sqrt{2001}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2001}}{2*3}=\frac{45+\sqrt{2001}}{6}
$