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5x*10x=86
We move all terms to the left:
5x*10x-(86)=0
Wy multiply elements
50x^2-86=0
a = 50; b = 0; c = -86;
Δ = b2-4ac
Δ = 02-4·50·(-86)
Δ = 17200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17200}=\sqrt{400*43}=\sqrt{400}*\sqrt{43}=20\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{43}}{2*50}=\frac{0-20\sqrt{43}}{100} =-\frac{20\sqrt{43}}{100} =-\frac{\sqrt{43}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{43}}{2*50}=\frac{0+20\sqrt{43}}{100} =\frac{20\sqrt{43}}{100} =\frac{\sqrt{43}}{5} $
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