5*(x-1)-3*(x+2)=(x+4)*2

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Solution for 5*(x-1)-3*(x+2)=(x+4)*2 equation: 


Simplifying
5(x + -1) + -3(x + 2) = (x + 4) * 2

Reorder the terms:
5(-1 + x) + -3(x + 2) = (x + 4) * 2
(-1 * 5 + x * 5) + -3(x + 2) = (x + 4) * 2
(-5 + 5x) + -3(x + 2) = (x + 4) * 2

Reorder the terms:
-5 + 5x + -3(2 + x) = (x + 4) * 2
-5 + 5x + (2 * -3 + x * -3) = (x + 4) * 2
-5 + 5x + (-6 + -3x) = (x + 4) * 2

Reorder the terms:
-5 + -6 + 5x + -3x = (x + 4) * 2

Combine like terms: -5 + -6 = -11
-11 + 5x + -3x = (x + 4) * 2

Combine like terms: 5x + -3x = 2x
-11 + 2x = (x + 4) * 2

Reorder the terms:
-11 + 2x = (4 + x) * 2

Reorder the terms for easier multiplication:
-11 + 2x = 2(4 + x)
-11 + 2x = (4 * 2 + x * 2)
-11 + 2x = (8 + 2x)

Add '-2x' to each side of the equation.
-11 + 2x + -2x = 8 + 2x + -2x

Combine like terms: 2x + -2x = 0
-11 + 0 = 8 + 2x + -2x
-11 = 8 + 2x + -2x

Combine like terms: 2x + -2x = 0
-11 = 8 + 0
-11 = 8

Solving
-11 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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