5*(2y-1)=7*(y+3)-2

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Solution for 5*(2y-1)=7*(y+3)-2 equation: 



5(2y-1)=7(y+3)-2

We move all terms to the left:

5(2y-1)-(7(y+3)-2)=0

We multiply parentheses

10y-(7(y+3)-2)-5=0



We calculate terms in parentheses: -(7(y+3)-2), so:

7(y+3)-2

We multiply parentheses

7y+21-2

We add all the numbers together, and all the variables

7y+19

Back to the equation:

-(7y+19)



We get rid of parentheses

10y-7y-19-5=0

We add all the numbers together, and all the variables

3y-24=0

We move all terms containing y to the left, all other terms to the right

3y=24

y=24/3

y=8

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