5(z-2)=-2(1-z)

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Solution for 5(z-2)=-2(1-z) equation: 



5(z-2)=-2(1-z)

We move all terms to the left:

5(z-2)-(-2(1-z))=0

We add all the numbers together, and all the variables

5(z-2)-(-2(-1z+1))=0

We multiply parentheses

5z-(-2(-1z+1))-10=0



We calculate terms in parentheses: -(-2(-1z+1)), so:

-2(-1z+1)

We multiply parentheses

2z-2

Back to the equation:

-(2z-2)



We get rid of parentheses

5z-2z+2-10=0

We add all the numbers together, and all the variables

3z-8=0

We move all terms containing z to the left, all other terms to the right

3z=8

z=8/3

z=2+2/3

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