5(z-2)+3(z-4)=10

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Solution for 5(z-2)+3(z-4)=10 equation:


Simplifying
5(z + -2) + 3(z + -4) = 10

Reorder the terms:
5(-2 + z) + 3(z + -4) = 10
(-2 * 5 + z * 5) + 3(z + -4) = 10
(-10 + 5z) + 3(z + -4) = 10

Reorder the terms:
-10 + 5z + 3(-4 + z) = 10
-10 + 5z + (-4 * 3 + z * 3) = 10
-10 + 5z + (-12 + 3z) = 10

Reorder the terms:
-10 + -12 + 5z + 3z = 10

Combine like terms: -10 + -12 = -22
-22 + 5z + 3z = 10

Combine like terms: 5z + 3z = 8z
-22 + 8z = 10

Solving
-22 + 8z = 10

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 8z = 10 + 22

Combine like terms: -22 + 22 = 0
0 + 8z = 10 + 22
8z = 10 + 22

Combine like terms: 10 + 22 = 32
8z = 32

Divide each side by '8'.
z = 4

Simplifying
z = 4

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