5(z+8)=4(z-3)+z

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Solution for 5(z+8)=4(z-3)+z equation: 


Simplifying
5(z + 8) = 4(z + -3) + z

Reorder the terms:
5(8 + z) = 4(z + -3) + z
(8 * 5 + z * 5) = 4(z + -3) + z
(40 + 5z) = 4(z + -3) + z

Reorder the terms:
40 + 5z = 4(-3 + z) + z
40 + 5z = (-3 * 4 + z * 4) + z
40 + 5z = (-12 + 4z) + z

Combine like terms: 4z + z = 5z
40 + 5z = -12 + 5z

Add '-5z' to each side of the equation.
40 + 5z + -5z = -12 + 5z + -5z

Combine like terms: 5z + -5z = 0
40 + 0 = -12 + 5z + -5z
40 = -12 + 5z + -5z

Combine like terms: 5z + -5z = 0
40 = -12 + 0
40 = -12

Solving
40 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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