5(z+7)=4(z-5)+z

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Solution for 5(z+7)=4(z-5)+z equation: 


Simplifying
5(z + 7) = 4(z + -5) + z

Reorder the terms:
5(7 + z) = 4(z + -5) + z
(7 * 5 + z * 5) = 4(z + -5) + z
(35 + 5z) = 4(z + -5) + z

Reorder the terms:
35 + 5z = 4(-5 + z) + z
35 + 5z = (-5 * 4 + z * 4) + z
35 + 5z = (-20 + 4z) + z

Combine like terms: 4z + z = 5z
35 + 5z = -20 + 5z

Add '-5z' to each side of the equation.
35 + 5z + -5z = -20 + 5z + -5z

Combine like terms: 5z + -5z = 0
35 + 0 = -20 + 5z + -5z
35 = -20 + 5z + -5z

Combine like terms: 5z + -5z = 0
35 = -20 + 0
35 = -20

Solving
35 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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