5(z+3)=(2z+1)

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Solution for 5(z+3)=(2z+1) equation: 



5(z+3)=(2z+1)

We move all terms to the left:

5(z+3)-((2z+1))=0

We multiply parentheses

5z-((2z+1))+15=0



We calculate terms in parentheses: -((2z+1)), so:

(2z+1)

We get rid of parentheses

2z+1

Back to the equation:

-(2z+1)



We get rid of parentheses

5z-2z-1+15=0

We add all the numbers together, and all the variables

3z+14=0

We move all terms containing z to the left, all other terms to the right

3z=-14

z=-14/3

z=-4+2/3

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