5(z+3)+2(2-1)=3z-11

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Solution for 5(z+3)+2(2-1)=3z-11 equation: 



5(z+3)+2(2-1)=3z-11

We move all terms to the left:

5(z+3)+2(2-1)-(3z-11)=0

We add all the numbers together, and all the variables

5(z+3)-(3z-11)+21=0

We multiply parentheses

5z-(3z-11)+15+21=0

We get rid of parentheses

5z-3z+11+15+21=0

We add all the numbers together, and all the variables

2z+47=0

We move all terms containing z to the left, all other terms to the right

2z=-47

z=-47/2

z=-23+1/2

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