5(z+2)=(3z-1)

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Solution for 5(z+2)=(3z-1) equation: 



5(z+2)=(3z-1)

We move all terms to the left:

5(z+2)-((3z-1))=0

We multiply parentheses

5z-((3z-1))+10=0



We calculate terms in parentheses: -((3z-1)), so:

(3z-1)

We get rid of parentheses

3z-1

Back to the equation:

-(3z-1)



We get rid of parentheses

5z-3z+1+10=0

We add all the numbers together, and all the variables

2z+11=0

We move all terms containing z to the left, all other terms to the right

2z=-11

z=-11/2

z=-5+1/2

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