5(z+1)=4(z+4)

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Solution for 5(z+1)=4(z+4) equation:


Simplifying
5(z + 1) = 4(z + 4)

Reorder the terms:
5(1 + z) = 4(z + 4)
(1 * 5 + z * 5) = 4(z + 4)
(5 + 5z) = 4(z + 4)

Reorder the terms:
5 + 5z = 4(4 + z)
5 + 5z = (4 * 4 + z * 4)
5 + 5z = (16 + 4z)

Solving
5 + 5z = 16 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
5 + 5z + -4z = 16 + 4z + -4z

Combine like terms: 5z + -4z = 1z
5 + 1z = 16 + 4z + -4z

Combine like terms: 4z + -4z = 0
5 + 1z = 16 + 0
5 + 1z = 16

Add '-5' to each side of the equation.
5 + -5 + 1z = 16 + -5

Combine like terms: 5 + -5 = 0
0 + 1z = 16 + -5
1z = 16 + -5

Combine like terms: 16 + -5 = 11
1z = 11

Divide each side by '1'.
z = 11

Simplifying
z = 11

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