5(z+1)=3(z+2)+11+z

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Solution for 5(z+1)=3(z+2)+11+z equation:


Simplifying
5(z + 1) = 3(z + 2) + 11 + z

Reorder the terms:
5(1 + z) = 3(z + 2) + 11 + z
(1 * 5 + z * 5) = 3(z + 2) + 11 + z
(5 + 5z) = 3(z + 2) + 11 + z

Reorder the terms:
5 + 5z = 3(2 + z) + 11 + z
5 + 5z = (2 * 3 + z * 3) + 11 + z
5 + 5z = (6 + 3z) + 11 + z

Reorder the terms:
5 + 5z = 6 + 11 + 3z + z

Combine like terms: 6 + 11 = 17
5 + 5z = 17 + 3z + z

Combine like terms: 3z + z = 4z
5 + 5z = 17 + 4z

Solving
5 + 5z = 17 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
5 + 5z + -4z = 17 + 4z + -4z

Combine like terms: 5z + -4z = 1z
5 + 1z = 17 + 4z + -4z

Combine like terms: 4z + -4z = 0
5 + 1z = 17 + 0
5 + 1z = 17

Add '-5' to each side of the equation.
5 + -5 + 1z = 17 + -5

Combine like terms: 5 + -5 = 0
0 + 1z = 17 + -5
1z = 17 + -5

Combine like terms: 17 + -5 = 12
1z = 12

Divide each side by '1'.
z = 12

Simplifying
z = 12

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