5(z+1)=2(3-2z)

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Solution for 5(z+1)=2(3-2z) equation:


Simplifying
5(z + 1) = 2(3 + -2z)

Reorder the terms:
5(1 + z) = 2(3 + -2z)
(1 * 5 + z * 5) = 2(3 + -2z)
(5 + 5z) = 2(3 + -2z)
5 + 5z = (3 * 2 + -2z * 2)
5 + 5z = (6 + -4z)

Solving
5 + 5z = 6 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
5 + 5z + 4z = 6 + -4z + 4z

Combine like terms: 5z + 4z = 9z
5 + 9z = 6 + -4z + 4z

Combine like terms: -4z + 4z = 0
5 + 9z = 6 + 0
5 + 9z = 6

Add '-5' to each side of the equation.
5 + -5 + 9z = 6 + -5

Combine like terms: 5 + -5 = 0
0 + 9z = 6 + -5
9z = 6 + -5

Combine like terms: 6 + -5 = 1
9z = 1

Divide each side by '9'.
z = 0.1111111111

Simplifying
z = 0.1111111111

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