5(y-7)=3(y-1)

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Solution for 5(y-7)=3(y-1) equation: 



5(y-7)=3(y-1)

We move all terms to the left:

5(y-7)-(3(y-1))=0

We multiply parentheses

5y-(3(y-1))-35=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

5y-3y+3-35=0

We add all the numbers together, and all the variables

2y-32=0

We move all terms containing y to the left, all other terms to the right

2y=32

y=32/2

y=16

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