5(y-7)=2y+3(y-2)

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Solution for 5(y-7)=2y+3(y-2) equation:


Simplifying
5(y + -7) = 2y + 3(y + -2)

Reorder the terms:
5(-7 + y) = 2y + 3(y + -2)
(-7 * 5 + y * 5) = 2y + 3(y + -2)
(-35 + 5y) = 2y + 3(y + -2)

Reorder the terms:
-35 + 5y = 2y + 3(-2 + y)
-35 + 5y = 2y + (-2 * 3 + y * 3)
-35 + 5y = 2y + (-6 + 3y)

Reorder the terms:
-35 + 5y = -6 + 2y + 3y

Combine like terms: 2y + 3y = 5y
-35 + 5y = -6 + 5y

Add '-5y' to each side of the equation.
-35 + 5y + -5y = -6 + 5y + -5y

Combine like terms: 5y + -5y = 0
-35 + 0 = -6 + 5y + -5y
-35 = -6 + 5y + -5y

Combine like terms: 5y + -5y = 0
-35 = -6 + 0
-35 = -6

Solving
-35 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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