5(y-6)+2(y+4)=13

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Solution for 5(y-6)+2(y+4)=13 equation:


Simplifying
5(y + -6) + 2(y + 4) = 13

Reorder the terms:
5(-6 + y) + 2(y + 4) = 13
(-6 * 5 + y * 5) + 2(y + 4) = 13
(-30 + 5y) + 2(y + 4) = 13

Reorder the terms:
-30 + 5y + 2(4 + y) = 13
-30 + 5y + (4 * 2 + y * 2) = 13
-30 + 5y + (8 + 2y) = 13

Reorder the terms:
-30 + 8 + 5y + 2y = 13

Combine like terms: -30 + 8 = -22
-22 + 5y + 2y = 13

Combine like terms: 5y + 2y = 7y
-22 + 7y = 13

Solving
-22 + 7y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 7y = 13 + 22

Combine like terms: -22 + 22 = 0
0 + 7y = 13 + 22
7y = 13 + 22

Combine like terms: 13 + 22 = 35
7y = 35

Divide each side by '7'.
y = 5

Simplifying
y = 5

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