5(y-5)=8y-28

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Solution for 5(y-5)=8y-28 equation: 



5(y-5)=8y-28

We move all terms to the left:

5(y-5)-(8y-28)=0

We multiply parentheses

5y-(8y-28)-25=0

We get rid of parentheses

5y-8y+28-25=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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