5(y-5)+2(y+4)=11

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Solution for 5(y-5)+2(y+4)=11 equation: 


Simplifying
5(y + -5) + 2(y + 4) = 11

Reorder the terms:
5(-5 + y) + 2(y + 4) = 11
(-5 * 5 + y * 5) + 2(y + 4) = 11
(-25 + 5y) + 2(y + 4) = 11

Reorder the terms:
-25 + 5y + 2(4 + y) = 11
-25 + 5y + (4 * 2 + y * 2) = 11
-25 + 5y + (8 + 2y) = 11

Reorder the terms:
-25 + 8 + 5y + 2y = 11

Combine like terms: -25 + 8 = -17
-17 + 5y + 2y = 11

Combine like terms: 5y + 2y = 7y
-17 + 7y = 11

Solving
-17 + 7y = 11

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 7y = 11 + 17

Combine like terms: -17 + 17 = 0
0 + 7y = 11 + 17
7y = 11 + 17

Combine like terms: 11 + 17 = 28
7y = 28

Divide each side by '7'.
y = 4

Simplifying
y = 4

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