5(y-4)=8y-32

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Solution for 5(y-4)=8y-32 equation: 



5(y-4)=8y-32

We move all terms to the left:

5(y-4)-(8y-32)=0

We multiply parentheses

5y-(8y-32)-20=0

We get rid of parentheses

5y-8y+32-20=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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