5(y-4)=8(2y+1)

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Solution for 5(y-4)=8(2y+1) equation: 



5(y-4)=8(2y+1)

We move all terms to the left:

5(y-4)-(8(2y+1))=0

We multiply parentheses

5y-(8(2y+1))-20=0



We calculate terms in parentheses: -(8(2y+1)), so:

8(2y+1)

We multiply parentheses

16y+8

Back to the equation:

-(16y+8)



We get rid of parentheses

5y-16y-8-20=0

We add all the numbers together, and all the variables

-11y-28=0

We move all terms containing y to the left, all other terms to the right

-11y=28

y=28/-11

y=-2+6/11

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