5(y-4)+2(y+3)=42

Solution for 5(y-4)+2(y+3)=42 equation:

Simplifying
5(y + -4) + 2(y + 3) = 42

Reorder the terms:
5(-4 + y) + 2(y + 3) = 42
(-4 * 5 + y * 5) + 2(y + 3) = 42
(-20 + 5y) + 2(y + 3) = 42

Reorder the terms:
-20 + 5y + 2(3 + y) = 42
-20 + 5y + (3 * 2 + y * 2) = 42
-20 + 5y + (6 + 2y) = 42

Reorder the terms:
-20 + 6 + 5y + 2y = 42

Combine like terms: -20 + 6 = -14
-14 + 5y + 2y = 42

Combine like terms: 5y + 2y = 7y
-14 + 7y = 42

Solving
-14 + 7y = 42

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 7y = 42 + 14

Combine like terms: -14 + 14 = 0
0 + 7y = 42 + 14
7y = 42 + 14

Combine like terms: 42 + 14 = 56
7y = 56

Divide each side by '7'.
y = 8

Simplifying
y = 8