5(y-3)=4(2y+1)-22

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Solution for 5(y-3)=4(2y+1)-22 equation: 



5(y-3)=4(2y+1)-22

We move all terms to the left:

5(y-3)-(4(2y+1)-22)=0

We multiply parentheses

5y-(4(2y+1)-22)-15=0



We calculate terms in parentheses: -(4(2y+1)-22), so:

4(2y+1)-22

We multiply parentheses

8y+4-22

We add all the numbers together, and all the variables

8y-18

Back to the equation:

-(8y-18)



We get rid of parentheses

5y-8y+18-15=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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