5(y-3)=2(6+y)

Solution for 5(y-3)=2(6+y) equation:

5(y-3)=2(6+y)

We move all terms to the left:

5(y-3)-(2(6+y))=0

We add all the numbers together, and all the variables

5(y-3)-(2(y+6))=0

We multiply parentheses

5y-(2(y+6))-15=0


We calculate terms in parentheses: -(2(y+6)), so:

2(y+6)

We multiply parentheses

2y+12

Back to the equation:

-(2y+12)


We get rid of parentheses

5y-2y-12-15=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9