5(y-3)=2(10-y)

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Solution for 5(y-3)=2(10-y) equation: 



5(y-3)=2(10-y)

We move all terms to the left:

5(y-3)-(2(10-y))=0

We add all the numbers together, and all the variables

5(y-3)-(2(-1y+10))=0

We multiply parentheses

5y-(2(-1y+10))-15=0



We calculate terms in parentheses: -(2(-1y+10)), so:

2(-1y+10)

We multiply parentheses

-2y+20

Back to the equation:

-(-2y+20)



We get rid of parentheses

5y+2y-20-15=0

We add all the numbers together, and all the variables

7y-35=0

We move all terms containing y to the left, all other terms to the right

7y=35

y=35/7

y=5

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