5(y-3)-9=-4(-8y+9)-9y

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Solution for 5(y-3)-9=-4(-8y+9)-9y equation: 



5(y-3)-9=-4(-8y+9)-9y

We move all terms to the left:

5(y-3)-9-(-4(-8y+9)-9y)=0

We multiply parentheses

5y-(-4(-8y+9)-9y)-15-9=0



We calculate terms in parentheses: -(-4(-8y+9)-9y), so:

-4(-8y+9)-9y

We add all the numbers together, and all the variables

-9y-4(-8y+9)

We multiply parentheses

-9y+32y-36

We add all the numbers together, and all the variables

23y-36

Back to the equation:

-(23y-36)



We add all the numbers together, and all the variables

5y-(23y-36)-24=0

We get rid of parentheses

5y-23y+36-24=0

We add all the numbers together, and all the variables

-18y+12=0

We move all terms containing y to the left, all other terms to the right

-18y=-12

y=-12/-18

y=2/3

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