5(y-3)-1=-2(-3y+5)-5y

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Solution for 5(y-3)-1=-2(-3y+5)-5y equation: 



5(y-3)-1=-2(-3y+5)-5y

We move all terms to the left:

5(y-3)-1-(-2(-3y+5)-5y)=0

We multiply parentheses

5y-(-2(-3y+5)-5y)-15-1=0



We calculate terms in parentheses: -(-2(-3y+5)-5y), so:

-2(-3y+5)-5y

We add all the numbers together, and all the variables

-5y-2(-3y+5)

We multiply parentheses

-5y+6y-10

We add all the numbers together, and all the variables

y-10

Back to the equation:

-(y-10)



We add all the numbers together, and all the variables

5y-(y-10)-16=0

We get rid of parentheses

5y-y+10-16=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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