5(y-3)+6=2(3y+1)

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Solution for 5(y-3)+6=2(3y+1) equation: 



5(y-3)+6=2(3y+1)

We move all terms to the left:

5(y-3)+6-(2(3y+1))=0

We multiply parentheses

5y-(2(3y+1))-15+6=0



We calculate terms in parentheses: -(2(3y+1)), so:

2(3y+1)

We multiply parentheses

6y+2

Back to the equation:

-(6y+2)



We add all the numbers together, and all the variables

5y-(6y+2)-9=0

We get rid of parentheses

5y-6y-2-9=0

We add all the numbers together, and all the variables

-1y-11=0

We move all terms containing y to the left, all other terms to the right

-y=11

y=11/-1

y=-11

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