5(y-2)+8y-6=8(y+9)-1

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Solution for 5(y-2)+8y-6=8(y+9)-1 equation: 



5(y-2)+8y-6=8(y+9)-1

We move all terms to the left:

5(y-2)+8y-6-(8(y+9)-1)=0

We add all the numbers together, and all the variables

8y+5(y-2)-(8(y+9)-1)-6=0

We multiply parentheses

8y+5y-(8(y+9)-1)-10-6=0



We calculate terms in parentheses: -(8(y+9)-1), so:

8(y+9)-1

We multiply parentheses

8y+72-1

We add all the numbers together, and all the variables

8y+71

Back to the equation:

-(8y+71)



We add all the numbers together, and all the variables

13y-(8y+71)-16=0

We get rid of parentheses

13y-8y-71-16=0

We add all the numbers together, and all the variables

5y-87=0

We move all terms containing y to the left, all other terms to the right

5y=87

y=87/5

y=17+2/5

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