5(y-1)-1=-3(-9y+3)-4y

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Solution for 5(y-1)-1=-3(-9y+3)-4y equation: 



5(y-1)-1=-3(-9y+3)-4y

We move all terms to the left:

5(y-1)-1-(-3(-9y+3)-4y)=0

We multiply parentheses

5y-(-3(-9y+3)-4y)-5-1=0



We calculate terms in parentheses: -(-3(-9y+3)-4y), so:

-3(-9y+3)-4y

We add all the numbers together, and all the variables

-4y-3(-9y+3)

We multiply parentheses

-4y+27y-9

We add all the numbers together, and all the variables

23y-9

Back to the equation:

-(23y-9)



We add all the numbers together, and all the variables

5y-(23y-9)-6=0

We get rid of parentheses

5y-23y+9-6=0

We add all the numbers together, and all the variables

-18y+3=0

We move all terms containing y to the left, all other terms to the right

-18y=-3

y=-3/-18

y=1/6

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