5(y+8)2y+1)=0

Solution for 5(y+8)2y+1)=0 equation:

5(y+8)2y+1)=0

We add all the numbers together, and all the variables

5(y+8)2y=0

We multiply parentheses

10y^2+80y=0

a = 10; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·10·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*10}=\frac{-160}{20}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*10}=\frac{0}{20}
=0
$