5(y+8)+y=4(y+4)+6

Solution for 5(y+8)+y=4(y+4)+6 equation:

5(y+8)+y=4(y+4)+6

We move all terms to the left:

5(y+8)+y-(4(y+4)+6)=0

We add all the numbers together, and all the variables

y+5(y+8)-(4(y+4)+6)=0

We multiply parentheses

y+5y-(4(y+4)+6)+40=0


We calculate terms in parentheses: -(4(y+4)+6), so:

4(y+4)+6

We multiply parentheses

4y+16+6

We add all the numbers together, and all the variables

4y+22

Back to the equation:

-(4y+22)


We add all the numbers together, and all the variables

6y-(4y+22)+40=0

We get rid of parentheses

6y-4y-22+40=0

We add all the numbers together, and all the variables

2y+18=0

We move all terms containing y to the left, all other terms to the right

2y=-18

y=-18/2

y=-9