5(y+4)-3(2y-4)=32

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Solution for 5(y+4)-3(2y-4)=32 equation: 


Simplifying
5(y + 4) + -3(2y + -4) = 32

Reorder the terms:
5(4 + y) + -3(2y + -4) = 32
(4 * 5 + y * 5) + -3(2y + -4) = 32
(20 + 5y) + -3(2y + -4) = 32

Reorder the terms:
20 + 5y + -3(-4 + 2y) = 32
20 + 5y + (-4 * -3 + 2y * -3) = 32
20 + 5y + (12 + -6y) = 32

Reorder the terms:
20 + 12 + 5y + -6y = 32

Combine like terms: 20 + 12 = 32
32 + 5y + -6y = 32

Combine like terms: 5y + -6y = -1y
32 + -1y = 32

Add '-32' to each side of the equation.
32 + -32 + -1y = 32 + -32

Combine like terms: 32 + -32 = 0
0 + -1y = 32 + -32
-1y = 32 + -32

Combine like terms: 32 + -32 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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