5(y+3)=3y+35

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Solution for 5(y+3)=3y+35 equation:



5(y+3)=3y+35
We move all terms to the left:
5(y+3)-(3y+35)=0
We multiply parentheses
5y-(3y+35)+15=0
We get rid of parentheses
5y-3y-35+15=0
We add all the numbers together, and all the variables
2y-20=0
We move all terms containing y to the left, all other terms to the right
2y=20
y=20/2
y=10

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