5(y+3)=-3(2y-4)

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Solution for 5(y+3)=-3(2y-4) equation: 



5(y+3)=-3(2y-4)

We move all terms to the left:

5(y+3)-(-3(2y-4))=0

We multiply parentheses

5y-(-3(2y-4))+15=0



We calculate terms in parentheses: -(-3(2y-4)), so:

-3(2y-4)

We multiply parentheses

-6y+12

Back to the equation:

-(-6y+12)



We get rid of parentheses

5y+6y-12+15=0

We add all the numbers together, and all the variables

11y+3=0

We move all terms containing y to the left, all other terms to the right

11y=-3

y=-3/11

y=-3/11

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