5(y+2)=18-(-1+3y)

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Solution for 5(y+2)=18-(-1+3y) equation: 



5(y+2)=18-(-1+3y)

We move all terms to the left:

5(y+2)-(18-(-1+3y))=0

We add all the numbers together, and all the variables

5(y+2)-(18-(3y-1))=0

We multiply parentheses

5y-(18-(3y-1))+10=0



We calculate terms in parentheses: -(18-(3y-1)), so:

18-(3y-1)

determiningTheFunctionDomain
-(3y-1)+18

We get rid of parentheses

-3y+1+18

We add all the numbers together, and all the variables

-3y+19

Back to the equation:

-(-3y+19)



We get rid of parentheses

5y+3y-19+10=0

We add all the numbers together, and all the variables

8y-9=0

We move all terms containing y to the left, all other terms to the right

8y=9

y=9/8

y=1+1/8

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