5(y+2)-4(y-1)=16

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Solution for 5(y+2)-4(y-1)=16 equation: 


Simplifying
5(y + 2) + -4(y + -1) = 16

Reorder the terms:
5(2 + y) + -4(y + -1) = 16
(2 * 5 + y * 5) + -4(y + -1) = 16
(10 + 5y) + -4(y + -1) = 16

Reorder the terms:
10 + 5y + -4(-1 + y) = 16
10 + 5y + (-1 * -4 + y * -4) = 16
10 + 5y + (4 + -4y) = 16

Reorder the terms:
10 + 4 + 5y + -4y = 16

Combine like terms: 10 + 4 = 14
14 + 5y + -4y = 16

Combine like terms: 5y + -4y = 1y
14 + 1y = 16

Solving
14 + 1y = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 1y = 16 + -14

Combine like terms: 14 + -14 = 0
0 + 1y = 16 + -14
1y = 16 + -14

Combine like terms: 16 + -14 = 2
1y = 2

Divide each side by '1'.
y = 2

Simplifying
y = 2

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