5(y+2)+3y=-3(3-y)+y-7

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Solution for 5(y+2)+3y=-3(3-y)+y-7 equation: 



5(y+2)+3y=-3(3-y)+y-7

We move all terms to the left:

5(y+2)+3y-(-3(3-y)+y-7)=0

We add all the numbers together, and all the variables

5(y+2)+3y-(-3(-1y+3)+y-7)=0

We add all the numbers together, and all the variables

3y+5(y+2)-(-3(-1y+3)+y-7)=0

We multiply parentheses

3y+5y-(-3(-1y+3)+y-7)+10=0



We calculate terms in parentheses: -(-3(-1y+3)+y-7), so:

-3(-1y+3)+y-7

We add all the numbers together, and all the variables

y-3(-1y+3)-7

We multiply parentheses

y+3y-9-7

We add all the numbers together, and all the variables

4y-16

Back to the equation:

-(4y-16)



We add all the numbers together, and all the variables

8y-(4y-16)+10=0

We get rid of parentheses

8y-4y+16+10=0

We add all the numbers together, and all the variables

4y+26=0

We move all terms containing y to the left, all other terms to the right

4y=-26

y=-26/4

y=-6+1/2

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