5(y+1)=-3(6y-1)+7y

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Solution for 5(y+1)=-3(6y-1)+7y equation: 



5(y+1)=-3(6y-1)+7y

We move all terms to the left:

5(y+1)-(-3(6y-1)+7y)=0

We multiply parentheses

5y-(-3(6y-1)+7y)+5=0



We calculate terms in parentheses: -(-3(6y-1)+7y), so:

-3(6y-1)+7y

We add all the numbers together, and all the variables

7y-3(6y-1)

We multiply parentheses

7y-18y+3

We add all the numbers together, and all the variables

-11y+3

Back to the equation:

-(-11y+3)



We get rid of parentheses

5y+11y-3+5=0

We add all the numbers together, and all the variables

16y+2=0

We move all terms containing y to the left, all other terms to the right

16y=-2

y=-2/16

y=-1/8

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