5(y+1)-7=3(3y-1)+2y

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Solution for 5(y+1)-7=3(3y-1)+2y equation: 



5(y+1)-7=3(3y-1)+2y

We move all terms to the left:

5(y+1)-7-(3(3y-1)+2y)=0

We multiply parentheses

5y-(3(3y-1)+2y)+5-7=0



We calculate terms in parentheses: -(3(3y-1)+2y), so:

3(3y-1)+2y

We add all the numbers together, and all the variables

2y+3(3y-1)

We multiply parentheses

2y+9y-3

We add all the numbers together, and all the variables

11y-3

Back to the equation:

-(11y-3)



We add all the numbers together, and all the variables

5y-(11y-3)-2=0

We get rid of parentheses

5y-11y+3-2=0

We add all the numbers together, and all the variables

-6y+1=0

We move all terms containing y to the left, all other terms to the right

-6y=-1

y=-1/-6

y=1/6

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