5(y+1)-7=(y-1)+2y

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Solution for 5(y+1)-7=(y-1)+2y equation: 



5(y+1)-7=(y-1)+2y

We move all terms to the left:

5(y+1)-7-((y-1)+2y)=0

We multiply parentheses

5y-((y-1)+2y)+5-7=0



We calculate terms in parentheses: -((y-1)+2y), so:

(y-1)+2y

We add all the numbers together, and all the variables

2y+(y-1)

We get rid of parentheses

2y+y-1

We add all the numbers together, and all the variables

3y-1

Back to the equation:

-(3y-1)



We add all the numbers together, and all the variables

5y-(3y-1)-2=0

We get rid of parentheses

5y-3y+1-2=0

We add all the numbers together, and all the variables

2y-1=0

We move all terms containing y to the left, all other terms to the right

2y=1

y=1/2

y=1/2

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