5(y+1)+8y=2(y-3)

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Solution for 5(y+1)+8y=2(y-3) equation: 



5(y+1)+8y=2(y-3)

We move all terms to the left:

5(y+1)+8y-(2(y-3))=0

We add all the numbers together, and all the variables

8y+5(y+1)-(2(y-3))=0

We multiply parentheses

8y+5y-(2(y-3))+5=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

13y-(2y-6)+5=0

We get rid of parentheses

13y-2y+6+5=0

We add all the numbers together, and all the variables

11y+11=0

We move all terms containing y to the left, all other terms to the right

11y=-11

y=-11/11

y=-1

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