5(x2)+2x=7(x+4)-38

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Solution for 5(x2)+2x=7(x+4)-38 equation: 



5(x2)+2x=7(x+4)-38

We move all terms to the left:

5(x2)+2x-(7(x+4)-38)=0

We add all the numbers together, and all the variables

5x^2+2x-(7(x+4)-38)=0



We calculate terms in parentheses: -(7(x+4)-38), so:

7(x+4)-38

We multiply parentheses

7x+28-38

We add all the numbers together, and all the variables

7x-10

Back to the equation:

-(7x-10)



We get rid of parentheses

5x^2+2x-7x+10=0

We add all the numbers together, and all the variables

5x^2-5x+10=0

a = 5; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·5·10
Δ = -175
Delta is less than zero, so there is no solution for the equation

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