5(x-8)+19=4x-2

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Solution for 5(x-8)+19=4x-2 equation: 



5(x-8)+19=4x-2

We move all terms to the left:

5(x-8)+19-(4x-2)=0

We multiply parentheses

5x-(4x-2)-40+19=0

We get rid of parentheses

5x-4x+2-40+19=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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