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5(x-8)+12=3(x-6)
We move all terms to the left:
5(x-8)+12-(3(x-6))=0
We multiply parentheses
5x-(3(x-6))-40+12=0
We calculate terms in parentheses: -(3(x-6)), so:We add all the numbers together, and all the variables
3(x-6)
We multiply parentheses
3x-18
Back to the equation:
-(3x-18)
5x-(3x-18)-28=0
We get rid of parentheses
5x-3x+18-28=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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