5(x-8)+10=4(x-3)+3

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Solution for 5(x-8)+10=4(x-3)+3 equation: 



5(x-8)+10=4(x-3)+3

We move all terms to the left:

5(x-8)+10-(4(x-3)+3)=0

We multiply parentheses

5x-(4(x-3)+3)-40+10=0



We calculate terms in parentheses: -(4(x-3)+3), so:

4(x-3)+3

We multiply parentheses

4x-12+3

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We add all the numbers together, and all the variables

5x-(4x-9)-30=0

We get rid of parentheses

5x-4x+9-30=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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