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5(x-6+5)=4(x-3+4)
We move all terms to the left:
5(x-6+5)-(4(x-3+4))=0
We add all the numbers together, and all the variables
5(x-1)-(4(x+1))=0
We multiply parentheses
5x-(4(x+1))-5=0
We calculate terms in parentheses: -(4(x+1)), so:We get rid of parentheses
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
5x-4x-4-5=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9
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