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5(x-6)-(x+5)=3(x-3)+(26-4x)
We move all terms to the left:
5(x-6)-(x+5)-(3(x-3)+(26-4x))=0
We add all the numbers together, and all the variables
5(x-6)-(x+5)-(3(x-3)+(-4x+26))=0
We multiply parentheses
5x-(x+5)-(3(x-3)+(-4x+26))-30=0
We get rid of parentheses
5x-x-(3(x-3)+(-4x+26))-5-30=0
We calculate terms in parentheses: -(3(x-3)+(-4x+26)), so:We add all the numbers together, and all the variables
3(x-3)+(-4x+26)
We multiply parentheses
3x+(-4x+26)-9
We get rid of parentheses
3x-4x+26-9
We add all the numbers together, and all the variables
-1x+17
Back to the equation:
-(-1x+17)
4x-(-1x+17)-35=0
We get rid of parentheses
4x+1x-17-35=0
We add all the numbers together, and all the variables
5x-52=0
We move all terms containing x to the left, all other terms to the right
5x=52
x=52/5
x=10+2/5
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