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5(x-5)=5(2-x)
We move all terms to the left:
5(x-5)-(5(2-x))=0
We add all the numbers together, and all the variables
5(x-5)-(5(-1x+2))=0
We multiply parentheses
5x-(5(-1x+2))-25=0
We calculate terms in parentheses: -(5(-1x+2)), so:We get rid of parentheses
5(-1x+2)
We multiply parentheses
-5x+10
Back to the equation:
-(-5x+10)
5x+5x-10-25=0
We add all the numbers together, and all the variables
10x-35=0
We move all terms containing x to the left, all other terms to the right
10x=35
x=35/10
x=3+1/2
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